I’m searching for a way to see if the numbers in a list = the numbers in a dictionary key. EX: dictionary = {12345:6, 01928:7} list = [1, 2, 3]. And the output would be like: the list fit in the key 12345.
@AZOM not nice, I agree
dict = {'12345':6, '01928':7}
list = [1, 2, 3]
for k in dict.keys():
ok = True
for e in list:
if str(e) not in k:
ok = False
break
if ok:
print('list in',k)
break
Better
dict = {'12345':6, '1928':7}
lst = [1, 2, 3]
for k in dict.keys():
if [x for x in lst if str(x) in k] == lst:
print('lst in',k)
break
dict = {'12345':6, '01928':7}
list = [1, 2, 3]
set_list = set(list)
found = []
for k in dict.keys():
if set([int(aK) for aK in k]) >= set_list:
found.append(k)
print(found)
Or, if readability is not much of a concern:
dict = {'12345':6, '01928':7}
list = [1, 2, 3]
found = [k for k in dict.keys() if set([int(aK) for aK in k]) >= set(list)]
print(found)
@pulbrich I like it.
You almost never need to use dict.keys().
dct = {"12345": 6, "01928": 7}
lst = [1, 2, 3, 12, 34, 234]
print("\n".join(key for key in dct if all(str(i) in key for i in lst)))
@ccc
Something I forgot to precise is that the keys in the dictionary are not strings but raw values (without the ‘’)