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I have a script that works great when run from within Pythonista. It calls another script by passing three arguments to it:

final = kraken(response['kraked_url'], path, name)

And this is what kraken() looks like:

def kraken(image_link,path,name):

However, when I run it as an iOS extension (which is what I really want to do), it ends up giving me this error:

TypeError: kraken() takes exactly 2 arguments (3 given)

What can I do to fix this?

What you have here looks like it should work. Could you please provide a minimal example that we can run that will throw this error?

It should work...

When I try this:

def kraken(a,b,c):
    var1 = a+10
    var2 = b+10
    var3 = c+10
    return(var1,var2,var3)

final = kraken(1,2,3)
print(final)

it prints:

(11,12,13)

without an Error

Can u post a bigger example?