Forum Archive

I'm sure I'm missing something obvious.

I added os.exit(EX_OK) after the v.present() line in my code, and when I run my app, Pythonista exists right away.

My code:
v = ui.load_view('umswi')
v.present()
os._exit(EX_OK)

If I remove the os._exit(EX_OK), my app runs until I press the "X" in the upper left-hand corner. If I put the os._exit(EX_OK) back in, my app starts and immediately exits.

If a user presses "X" in the upper left-hand corner, I want Pythonista to close. But I don't want it to close until someone presses that "X".

What am I doing wrong?

you want a wait_modal in order to stop execution until the user closes the view -- present does not block. The ui operates on a different thread effectively from the main script.

I added a wait_model() line after the present() line, but it seems to block access to the camera.

Any tips there?

@cgallery Here's something you can try: Define a custom View class like this:

class ExitingView (ui.View):
    def will_close(self):
        os._exit(0)

Then, in your pyui file, enter ExitingView (or whatever class name you chose) in "Custom View Class" for the main view (show the inspector with nothing selected).

The will_close method will be called automatically when the "X" is tapped.

Thank you I will try that.

Huh, that also blocks the camera.

I have @ui.in.background before the line that takes the picture with the built-in camera. So that code looks like this:

@ui.in.background
def button_camera(sender):
if len(pics) == 4:
pics.pop(0)
pic = photos.capture_image()
if pic:
pics[len(pics):] = [pic]
showpics(sender)

So in my ui, I have a button with an action set to button_camera.

@cgallery Hmm, I think this may actually be a bug in photos.capture_image. I'll look into it, but I can't think of a workaround right now.

Well I can change my code and add an Exit button or something, I'll figure out some way to work around this.

Thanks for all your help.