Is this the best way to say output a list of say the 10 closest birthday? I think not. Thank
```
import contacts
from datetime import datetime
import operator
import workflow
import dialogs
days_list = []
people = contacts.get_all_people()
now = datetime.now()
for p in people:
b = p.birthday
if b:
next_birthday = datetime(now.year, b.month, b.day)
if next_birthday < now:
next_birthday = datetime(now.year + 1, b.month, b.day)
days = (next_birthday - now).days
days_list.append({'name': p.full_name, 'days': days})
if not days_list:
print 'You don\'t have any birthdays in your address book.'
else:
days_list.sort(key=operator.itemgetter('days'))
for item in days_list[:1]:
text = ' %s in %i days' % (item['name'], item['days'])
for item in days_list[:2]:
text2 = ' %s in %i days' % (item['name'], item['days'])
for item in days_list[:3]:
text3 = ' %s in %i days' % (item['name'], item['days'])
for item in days_list[:4]:
text4 = ' %s in %i days' % (item['name'], item['days'])
for item in days_list[:5]:
text5 = '* %s in %i days' % (item['name'], item['days'])
birthday_list = '\n'.join([text, text2, text3,text4,text5])
workflow.set_output(birthday_list)```